Can someone explain the Hall Effect? If electrons are moving inside a magnetic field that is perpendicular to the wire, then perpendicular to both the wire and the magnetic field will be a resultant voltage? Why does this voltage arise?
Why is it that when two hydrogen atoms combine together, their combined energy is less than the energy of one hydrogen atom by itself? Why wouldn't the combined energy be twice as much?
When both J and K are 0, then there is no change in outputs.
When they are both 1, then the outputs are toggled.
A B Y Next X Next Y
0 0 0
I still get stuck at this part. I can tell that next Y is going to be 0, but I can't say what next X is, because the table doesn't tell me what X...
A B Y Next X Next Y
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
I'm a little bit confused as to what to do after this. I see the equation AB'Y + A'BY' going into J and K. So that means that J and K will always be the same. Is that right?
Homework Statement
(a) How many states does this system have?
(b) How many rows will there be in a state transition table?
(c) Provide the state transition table.
(d) Draw a state diagram of the system.
(e) Describe what the circuit does in words.
Homework Equations
The Attempt at a...
What is the effective mass of a charge carrier, numerically? Is it equivalent to the mass of an electron? Is it the same for negative charge carriers as it is for positive charge carriers?
In Cadence we built a CMOS inverter. I made a transient response graph showing the input and output voltage waveforms. We're supposed to measure rise delay and fall delay of the output voltage. How do I do this? I heard from someone else that it's where the graphs cross 1.5V, but I'm still...
How about this. Since the probability of finding the particle outside the box with dimensions Lx and Ly is 0, then the wavefunction must go to 0 outside of these limits.
V is not in the denominator so it will not make anything go to 0. It will just create an infinitely large number.
A wavefunction is continuous and therefore differentiable everywhere. So at the boundaries it will also be differentiable.
I thought that in the equation there are two Ys. One is Y(x) and the other is Y(y). So Y is actually Y(x,y)?
I don't know what to say about those equations. Any hints?
How is it that X = Ae^(ikx) + Be^(-ikx) is the same as X(x)=Asin(kx)+BCos(kx)? Is there a name for that rule?
If C = 0, I don't see why that doesn't turn
X = Ae^(sqrt(C)x) + Be^(-sqrt(C)x)
into
X = Ae^0 + Be^0
Just plug in right?
X = Ae^(sqrt(C)x) + Be^(-sqrt(C)x)
if C = k^2 then the equation is
X = Ae^(kx) + Be^(-kx)
if C = -k^2 then it is
X = Ae^(ikx) + Be^(-ikx) (not sure about this one)
if C = 0 then it is
X = Ae^0 + Be^0 = A + B
X'' - CX = 0
r^2 - C = 0
r^2 = C
r1 = C
r2 = -C
X = Ae^(Cx) + Be^(-Cx)
Is that much correct? Now do I plugin initial and final conditions to solve for the constants, or do I first have to find the particular solution?
It's been a while so I'm not too confident with solving the ODE. I think that I have to create a characteristic equation, and I'll find solutions s1 and s2, and plug that in to an equation like Ae^(s1)+Be^(s2), then plugin initial values to find A and B? Is it something like that?
Yes, functions of a variable can be equal to a constant, I just suspected that wasn't the case here.
If X''(x)/X(x) = C, then
X(x)''/X(x) + Y(y)''/Y(y) = -2m/h^2*E
C + Y(y)''/Y(y) = -2m/h^2*E
Y(y)''/Y(y) = -2m/h^2*E - C
If that is correct, then I think that the integral should be taken...
If both functions are constant, then adding them together would result in a constant, but I don't see how they can be constants since they have variables in them.
Yes, x and y are independent. A function of x and a function of y added together will result in a constant when the variables cancel each other out or become 0.
X''(x)/X(x) is a function of x and Y''(y)/Y(y) is a function of y.
Are you asking when
X(x)''/X(x) + Y(y)''/Y(y) + 2m/h^2*E = 0
will be equal to 2m/h^2*E = 0 ?
If that's the case, then it will happen either when both X(x)''/X(x) and Y(y)''/Y(y) are equal to 0, or when X(x)''/X(x) =...